trig question!

Question

0

543

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Thanks a million guys! #Melody & #CPhill, your answers were so helpful, both of you are wise and nice!

But I'm still struggling with my homework 😭

How do you solve this trig equation. Where 0< x <360

(sinx+1)² - 2sinx = 0

I appreciate your advices.

Steven434 Nov 25, 2015

CPhill · Answer 1 · 2015-11-25T11:51:43

(sinx + 1)^2 - 2sinx = 0

sin^2x + 2sinx + 1 - 2sinx = 0

sin^2x + 1 = 0

sin^2x = -1

Notice that the square of any non-zero value of the sine is always positive.....so.......this has no real solution(s).....!!!!!