In right triangle ABC with B = 90 , we have 2 sin A = 5 cos A. What is tan A?
In right triangle ABC with B = 90 , we have 2 sin A = 5 cos A. What is tan A?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
2(sinA) = 5(cosA)
sinA = 2.5(cosA)
We know that (sinA)2 + (cosA)2 = 1
x2 + (x / 2.5)2 = 1
x = 0.92847669 (x = sinA)
cosA = x / 2.5 = 0.371390676
Angle A = 68.19859051º
tanA = sinA / cosA