What is the sine of an acute angle whose cosine is 7/25?
cos(-1)=.28
cos=73.740deg
sin73.740=0.96
(0.28)2 + (0.96)2 = 1
Your answer is correct!
Remmber, fo an angle:
sin^2 + cos^2 = 1
(7/25)^2 + cos^2 = 1
1- (7/25)^2 = cos ^2
576/625 = cos^2
sqrt 576 / 25 = cos = 24/25