Could someone walk me through this problem? I'm not sure if I'm doing the right things. "Find the exact value of the remaining trig ratios for (theta) if cot(theta)= 4/7 Thanks!
+128460 cot Θ = x/y = 4/7
tan Θ = y/x = 7/4
For the rest of the identities we need to find "r"....this is given by √[x^2 + y^2] = √[4^2 + 7^2] = √65
So
sin Θ = y/r = 7/ √65
cosec Θ is the reciprocal of the sine = √65/7
cos Θ = x / r = 4/ √65
sec Θ is the reciprocal of the cos = √65/4
+128460 cot Θ = x/y = 4/7
tan Θ = y/x = 7/4
For the rest of the identities we need to find "r"....this is given by √[x^2 + y^2] = √[4^2 + 7^2] = √65
So
sin Θ = y/r = 7/ √65
cosec Θ is the reciprocal of the sine = √65/7
cos Θ = x / r = 4/ √65
sec Θ is the reciprocal of the cos = √65/4
