+9665 Let a triangle with any two sides with length a and b exists.
Let the angle between a and b be \(\theta\)
The height 'h' = \(a\sin \theta \)OR \(b\sin \theta\)
The base = b if "height = a sin theta" is true OR = a if "height = b sin theta" is true.
Therefore Area of Any Triangle = \(\dfrac{ab\sin \theta}{2}\)
