From points P and Q, 180 meters apart on an east-west line, a tree is sighted on the opposite side of a
deep ravine. From point P, a compass indicates that the bearing of the tree is 27°. From Q, the bearing
of the tree is 43°. How far from P is the tree? (Hint: When you draw a diagram, Q is to the left of P.)
You must show the equation(s) you used to solve the problem and explain your solution. Give your
answers with lengths rounded to 4 significant digits and angles rounded to 1 decimal place.
Actually the second angle is 27 degrees not 23 degrees could you please re submit your answer
If you use the law of sines (the third angle of the triangle = 180 -43-23= 114 degrees
sin 114/180 = sin43/d results in d=134.37 m= 134.4 m (four sig dig)
Actually the second angle is 27 degrees not 23 degrees could you please re submit your answer
Sorry...'my bad' ...as they say
The third angle of the triangle would be 180 -27-43 =110 degrees
then the Law of Sines equation becomes....
(sin 110) /180 = (sin 43) /d then d = 130.6 m