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From points P and Q, 180 meters apart on an east-west line, a tree is sighted on the opposite side of a
deep ravine. From point P, a compass indicates that the bearing of the tree is 27°. From Q, the bearing
of the tree is 43°. How far from P is the tree? (Hint: When you draw a diagram, Q is to the left of P.)
You must show the equation(s) you used to solve the problem and explain your solution. Give your
answers with lengths rounded to 4 significant digits and angles rounded to 1 decimal place.

 Dec 27, 2016

Best Answer 

 #2
avatar+180 
+5

Actually the second angle is 27 degrees not 23 degrees could you please re submit your answer

 Dec 27, 2016
 #1
avatar+37153 
0

If you use the law of sines  (the third angle of the triangle = 180 -43-23= 114 degrees

 

sin 114/180 = sin43/d   results in d=134.37 m= 134.4 m (four sig dig)

 Dec 27, 2016
edited by ElectricPavlov  Dec 27, 2016
 #2
avatar+180 
+5
Best Answer

Actually the second angle is 27 degrees not 23 degrees could you please re submit your answer

Sebast1ani5dumb  Dec 27, 2016
 #3
avatar+37153 
+5

Sorry...'my bad' ...as they say

 

The third angle of the triangle would be   180 -27-43 =110 degrees

then the Law of Sines equation becomes....

(sin 110) /180 = (sin 43) /d      then d = 130.6 m

 Dec 27, 2016
edited by ElectricPavlov  Dec 27, 2016

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