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In right triangle ABC, we have AB = 10, BC = 20, and angle ABC = 90. If M is on AC such that BM is a median of triangle ABC, then what is cos ABM?

 Jul 26, 2021
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cos(∠ABM) = √(1/5) = 0.447213595

 Jul 26, 2021
edited by Guest  Jul 26, 2021

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