+118724 sin (tan^-1(-3))
\(let\;\;\theta = atan(-3)\)
since tan of theta=-3 the answer must be in the 2nd or 4th quad.
so sin(theta) can be poitive or negative.
The picture insert is not working and I have not worked out Alan's method 
yet so you will find the pic here.
https://gyazo.com/e675c1683e43acefde22093a14baedf3
\(sin (tan^{-1}(-3))=\frac{\pm3\sqrt{10}}{10}\)
+130518 tan-1 (-3) = -71.565051177078°
So
sin (-71.565051177078°) = -0.948683298051
+118724 sin (tan^-1(-3))
\(let\;\;\theta = atan(-3)\)
since tan of theta=-3 the answer must be in the 2nd or 4th quad.
so sin(theta) can be poitive or negative.
The picture insert is not working and I have not worked out Alan's method yet so you will find the pic here.
https://gyazo.com/e675c1683e43acefde22093a14baedf3
\(sin (tan^{-1}(-3))=\frac{\pm3\sqrt{10}}{10}\)
