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Find AC in the diagram below

 

[asy]

size(140);

pair A,B,C,O;

A=(-cot(5pi/12),0);
B=(cot(pi/4),0);
C=(0,1);

draw(A--B--C--cycle);

dot("$A$",A,SW);
dot("$B$",B,SE);
dot("$C$",C,N);

label("$75^\circ$",A,2dir(32));
label("$45^\circ$",B,3dir(155));
label("$30$",A--B,S);
[/asy]

 Jun 22, 2022
 #1
avatar
0

AC = 12*sqrt(3).

 Jun 23, 2022

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