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In triangle BCD, angle C = 90 degrees, CD = 3, and BD = $\sqrt 13$ . What is $\tan B$ ?

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Best Answer

First find CB via pythag theorem CB = 2 (sqrt ( sqrt13² - 3²)

Then tan = opp/adj = CD / CB = 3/2

Guest Feb 5, 2021

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Thank you!

Guest · Answer 1 · 2021-02-05T06:31:00

First find CB via pythag theorem CB = 2 (sqrt ( sqrt13² - 3²)

Then tan = opp/adj = CD / CB = 3/2