+0  
 
0
51
2
avatar+102 

In triangle BCD, angle C = 90 degrees, CD = 3, and BD = \(\sqrt 13\). What is \(\tan B\)?

 Feb 5, 2021

Best Answer 

 #1
avatar
+1

First find CB via pythag theorem       CB = 2            (sqrt ( sqrt132 - 32)

 

Then tan = opp/adj = CD / CB =  3/2

 Feb 5, 2021
 #1
avatar
+1
Best Answer

First find CB via pythag theorem       CB = 2            (sqrt ( sqrt132 - 32)

 

Then tan = opp/adj = CD / CB =  3/2

Guest Feb 5, 2021
 #2
avatar+102 
+1

Thank you!

vockeyvockvock  Feb 5, 2021

25 Online Users