What is this equation's answer
h= [18(tan9)*tan(3.5)]/tan(9)-tan(3.5)
\(h=\frac{18(tan 9)(tan3.5)}{tan 9}-tan3.5\)
deg \(h=\frac{18(tan 9)(tan3.5)}{tan 9}-tan3.5=1.03976454256\)
rad \(h=\frac{18(tan 9)(tan3.5)}{tan 9}-tan3.5=6.36795588271\)
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\(\quad h\\ = \dfrac{18\tan 9 \tan 3.5}{\tan 9}-\tan 3.5\\ =18\tan 3.5 - \tan 3.5\\ = 17\tan 3.5\)
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