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What would be the angles of a triangle, that has the sides of a=22.4, b=15.8, c=8.6 Using sine and cosine law
 Dec 17, 2013
 #1
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DGenovese:

What would be the angles of a triangle, that has the sides of a=22.4, b=15.8, c=8.6 Using sine and cosine law



You will need to use the cosine rule to find the first angle because you need an angle before you can use sine rule.
for the second angle you can use sine or cosine rule. It doesn't matter which one although sine rule is easier to work with.
The third angle is super easy to find.

Now, do you know what the cosine rule is?
It will be easiest if you start it in the form CosA=...

Now it is your turn to show me what you can do.
 Dec 17, 2013
 #2
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It would be CosA=b^2+c^2-a^2/2bc
 Dec 17, 2013
 #3
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DGenovese:

It would be CosA=b^2+c^2-a^2/2bc



Yes but you need the brackets
On paper you probably had a big fraction so the brackets are implied but here you need to put the brackets in.

CosA=(b^2+c^2-a^2)/(2bc)

okay, now substitute in a, b and c in and get the value of CosA and then get the value for A.
 Dec 17, 2013

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