Given sin(−θ)=−1/6 and tanθ=−35√/35.
What is the value of cosθ?
sin (-theta) = -sin theta so sin (theta) = 1/6
sin^2 + cos^2 = 1
sqrt(1- ( 1/6)2 ) = cos = +- sqrt (35/36)
but tan is negative and sin is positive so cos is neagative :
- sqrt (35/36) = sqrt35 / 6 = cos
