+14986 Solve triangle ABC if C = 117.2 deg, A = 28.8 deg and b = 75.6 ft.
\(Triangle ABC:\ \color{blue}\gamma=117.2deg, \ \alpha=28.8 deg, \ b=75.6 ft.\)
\(\beta = 180deg - \alpha-\gamma=(180-28.8-117.2)deg\)
\(\beta =34deg \)
\(b:sin\beta=a:sin\alpha\)
\(a=\frac{bsin\alpha}{sin\beta}=\frac{75.6ft\times sin28.8deg}{sin34deg}\)
\(a=65.131ft\)
\(b:sin\beta=c:sin\gamma\)
\(c=\frac{bsin\gamma}{sin\beta}=\frac{75.6ft\times sin117.2deg}{sin34deg}\)
\(c=120.245ft\)
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