cot^-1(-sqrt(11))
x=cot−1(−√11)|cot()cot(x)=−√11|cot(x)=1tan(x)1tan(x)=−√11tan(x)=1−√11|arctan()x=arctan(1−√11)cot−1(−√11)=arctan(1−√11)=arctan(1−3.31662479036)=arctan(−0.30151134458)=−16.7786548810∘
heureka has given the angle in the fourth quadrant. There is also an angle in the second quadrant that satisfies the condition; namely 163.221°
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