+0  
 
0
569
2
avatar

2sin^2x+cosx=1

 Nov 10, 2015

Best Answer 

 #1
avatar+118723 
+10

2sin^2x+cosx=1

 

\(2sin^2x+cosx=1\\ 2(1-cos^2x)+cosx=1\\ 2-2cos^2x+cosx=1\\ -2cos^2x+cosx+1=0\\ 2cos^2x-cosx-1=0\\let\;\;m=cosx\\ 2m^2-m-1=0\\ m^2-(1/2)m-(1/2)=0\\ (m-1)(m+1/2)=0\\ m=1 \;\;or\;\; m=-1/2\\ cosx=1\qquad or \qquad cosx=-1/2\\ x=0+360n \qquad or \qquad 180\pm60+360n\qquad where\;\;n\in z\\ x=360n \qquad or \qquad x=180+60+360n\qquad or \qquad x=180-60+360n \qquad where\;\;n\in z\\ x=360n \qquad or \qquad x=240+360n\qquad or \qquad x=120+360n \qquad where\;\;n\in z\\ \mbox{x is in degrees}\)

 Nov 10, 2015
 #1
avatar+118723 
+10
Best Answer

2sin^2x+cosx=1

 

\(2sin^2x+cosx=1\\ 2(1-cos^2x)+cosx=1\\ 2-2cos^2x+cosx=1\\ -2cos^2x+cosx+1=0\\ 2cos^2x-cosx-1=0\\let\;\;m=cosx\\ 2m^2-m-1=0\\ m^2-(1/2)m-(1/2)=0\\ (m-1)(m+1/2)=0\\ m=1 \;\;or\;\; m=-1/2\\ cosx=1\qquad or \qquad cosx=-1/2\\ x=0+360n \qquad or \qquad 180\pm60+360n\qquad where\;\;n\in z\\ x=360n \qquad or \qquad x=180+60+360n\qquad or \qquad x=180-60+360n \qquad where\;\;n\in z\\ x=360n \qquad or \qquad x=240+360n\qquad or \qquad x=120+360n \qquad where\;\;n\in z\\ \mbox{x is in degrees}\)

Melody Nov 10, 2015
 #2
avatar+130517 
0

Nice, Melody.......those substitutions make this problem easier....!!!

 

 

 

cool cool cool

 Nov 10, 2015

2 Online Users

avatar