Find all values of x in the interval [0, 2π] that satisfy the equation.
14 sin^2(x) = 7
14sin (2x) = 7 divide both sides by 14
sin (2x) = 7/14
sin (2x) = 1 / 2
So...
sin (2x) = 1/2 at pi/6 , 5pi / 6 , 13 pi / 6 , 17 pi / 6 divide both sides by 2
x = pi /12 , 5pi/12, 13 pi / 12 and 17pi /12
