Find all values of x in the interval [0, 2π] that satisfy the equation.

3 sin(2x) = 3 cos(x)

I got the equation to be " sin x = 0 " I think that is right but I'm not sure

Ruublrr Jan 23, 2019

#1**+1 **

3 sin2x = 3 cos x divide by 3

sin 2x = cos x

2 sin cos = cos

2sin =1

sin x = 1/2 pi/6 and 5pi/6

ElectricPavlov Jan 23, 2019