Find all values of x in the interval [0, 2π] that satisfy the equation.
3 sin(2x) = 3 cos(x)
I got the equation to be " sin x = 0 " I think that is right but I'm not sure
3 sin2x = 3 cos x divide by 3
sin 2x = cos x
2 sin cos = cos
sin x = 1/2 pi/6 and 5pi/6
Ohhhh i subtracted the cos x instead of dividing it
Figured that ! I've done the same....