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avatar+322 

Find all values of x in the interval [0, 2π] that satisfy the equation.

 

3 sin(2x) = 3 cos(x)

 

I got the equation to be " sin x = 0 "  I think that is right but I'm not sure

 Jan 23, 2019
 #1
avatar+18961 
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3 sin2x = 3 cos x         divide by 3

sin 2x = cos x

2 sin cos = cos

2sin =1

sin x = 1/2     pi/6   and   5pi/6

 Jan 23, 2019
 #2
avatar+322 
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Ohhhh i subtracted the cos x instead of dividing it

Ruublrr  Jan 23, 2019
 #3
avatar+18961 
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Figured that !   I've done the same....   cheeky

ElectricPavlov  Jan 23, 2019

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