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# trig

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In triangle $PQR$, we have $\angle P = 90^\circ$, $QR = 15$, and $\tan R = 5\cos Q$. What is $PQ$?

Apr 26, 2021

#1
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PQ = 8*sqrt(3).

Apr 26, 2021
#2
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tan(R) = 5 * sin(R)

Angle R ≈ 78.46304º

PQ = sin(R) * QR

Apr 26, 2021