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In triangle $PQR$, we have $\angle P = 90^\circ$, $QR = 15$, and $\tan R = 5\cos Q$. What is $PQ$?

 Apr 26, 2021
 #1
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PQ = 8*sqrt(3).

 Apr 26, 2021
 #2
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tan(R) = 5 * sin(R)

 

Angle R ≈ 78.46304º

 

PQ = sin(R) * QR

 Apr 26, 2021

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