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In triangle BCD, angle C = 90 degrees, CD = 3, and BD = sqrt(14) . What is tan B?

 Aug 2, 2021
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Find CB via pythag theorem

3^2 + CB^2 = 14

CB = sqrt(5)

 

Tan B = opp/adj = 3 / sqrt(5)    or  3/5  * sqrt5

 Aug 2, 2021

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