If cosθ=513 and 0<θ<π2 . Then what is the value of cosθ+5cotθ÷cscθ−cosθ ?
Hi Buubleman :)
Draw a right angled triange.
put theta in one of the acute angles.
cos theta = 5/13
So adjacent side is 5 and the hypotenuse is 13
Us pythagotean theorum to find the opposite side and it is 12
now you should be able find all the rations and put them together as you hve been asked :)
Hi Buubleman :)
Draw a right angled triange.
put theta in one of the acute angles.
cos theta = 5/13
So adjacent side is 5 and the hypotenuse is 13
Us pythagotean theorum to find the opposite side and it is 12
now you should be able find all the rations and put them together as you hve been asked :)