Use trig to solve for length of CF
We know that BC is 50 and FBC is 30°
CF/BC = tan30
CF/50 = tan30
CF/50 = 0.57735
CF = 28.8675
Use Pythagorean theorem to solve for length of AC
AC^2 = AB^2 + BC^2
AC^2 = 70^2 + 50^2 = 4900 + 2500 = 7400
AC = square root of 7400
AC = 86.0232
Use trig to solve for angle FAC
tan FAC = CF/AC
tan FAC = 28.8675/86.0232 = 0.33557
angle FAC = tan^-1 of 0.33557
angle FAC = 18.550°
Thank you!
