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An air force pilot must descend 1500 feet over a distance of 9000 feet to land smoothly on aircraft carrier. What is the plane's angle descent?

Guest Apr 11, 2012

CubeyThePenguin · Answer 1 · 2021-02-20T03:11:27

The angle of descent is \(\tan^{-1}(\frac{1500}{9000}) = \boxed{9.46^{\circ}}\)