What are the solutions to the trigonometric equation on the interval [0,2π)?
2cos^2x=cosx
Select all correct solutions.
0
π6
π3
π2
2π3
5π6
π
7π6
4π3
3π2
5π3
11π6
2cos^2x=cosx Divide both sides of th equation by cos
2 cos x = 1
cos x = 1/2
x = pi/3 5 pi / 3