Right △ABC has its right angle at C, BC=4 , and AC=8 .
What is the value of the trigonometric ratio?
COT B =
COS A =
CSC B =
AB = √ [4^2 + 8^2 ] = √ 80 = 4√5
COT B = BC / AC = 4 / 8 = 1 / 2
COS A = AC / AB = 8 / [ 4√5 ] = 2 / √5 = 2√5 / 5
CSC B = AB / AC = 4√5 / 8 = √5 / 2