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A Ferris wheel starts spinning at t = 0 s and stops at t = 12 s. If the Ferris wheel made 5 loops during that time, what is its period, k? a. 5π /26 b. 2π /5 c. 2π/ 12 d. 2π The answer I got was 5π/6 because I divided 12s by 5 (=2.4), then I divided 2π by that to get the period. The answer in the back says (a) but I don't know how to get this, please help!

Guest Jun 7, 2017

Best Answer 

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The Ferris wheel takes 12/5 seconds per rotation (a very fast Ferris wheel!) : This is the period.

 

This is 12/(5*2pi) seconds per radian

 

The frequency is 5/12 rotations per second (Hz) or 5*2pi/12 radians per second.

.

Alan  Jun 7, 2017
 #1
avatar+26755 
0
Best Answer

The Ferris wheel takes 12/5 seconds per rotation (a very fast Ferris wheel!) : This is the period.

 

This is 12/(5*2pi) seconds per radian

 

The frequency is 5/12 rotations per second (Hz) or 5*2pi/12 radians per second.

.

Alan  Jun 7, 2017

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