i need help with some trigonometric problems. i really dont understand. please help me!!

Guest Nov 1, 2017

#5**0 **

I wish I could help, but I haven't learned about cosecants and cotangents.

Sorry!

:)

ZZZZZZ
Nov 1, 2017

#6**+2 **

[ sin x * tan x ] + cos x = sec x

[sin x * sin x / cos x ] + cos x = sec x

[ sin^2 x / cos x] + cos x = sec x ... get a common denominator on the left

[sin^2 x / cos x] + [cos^2 x / cos x ] = sec x .... sin^2 x + cos^2 x = 1

[ sin^2 x + cos^2 x] / cos x = sec x

1 / cos x = sec x

CPhill
Nov 1, 2017