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# trigonometric

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Guest Nov 1, 2017
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#1
+445
+1

what are the problems?

ZZZZZZ  Nov 1, 2017
#3
0

1. senx tgx + cosx = secx

2. cosecx=senxcotgx cosx

3.(senx+cosx)^2+(senx = cosx)^2=2

those are some but i still have another ones.

Guest Nov 1, 2017
#4
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do you an email where i can send you the pic of all the problems.

Guest Nov 1, 2017
#2
+549
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yeah thats what i was thinking..

ProMagma  Nov 1, 2017
#5
+445
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I wish I could help, but I haven't learned about cosecants and cotangents.

Sorry!

:)

ZZZZZZ  Nov 1, 2017
#6
+84129
+2

[ sin x  * tan x ]  + cos x  =   sec x

[sin x *  sin x / cos x ]  +  cos x  = sec x

[ sin^2 x  /  cos x]  + cos x =  sec x            ...  get a common denominator on the left

[sin^2 x  /  cos x]  +  [cos^2 x / cos x ] =  sec x        .... sin^2 x  + cos^2 x = 1

[ sin^2 x  + cos^2 x] / cos x    =   sec x

1 / cos x   =  sec x

CPhill  Nov 1, 2017

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