+1632 Hypotenuse = 3sqrt(15)
Shorter Leg = 3 sqrt(6)
By pythagorean theorem, Longer Leg = 9
Let the point between the hypotenuse and the shorter leg be A. We know that point A must have the largest acute angle in the triangle by construction.
Using any trig function (preferably a easy-calculation one), such as sinA, we can use the inverse function of it to find the angle.
sinA = opposite/hypotenuse = 9/3sqrt(15) = 3sqrt(15)/15 = sqrt(15)/5
Then angle A = arcsin(sqrt(15)/5) = 0.886 radians = 50.8 degrees.
+1632 Hypotenuse = 3sqrt(15)
Shorter Leg = 3 sqrt(6)
By pythagorean theorem, Longer Leg = 9
Let the point between the hypotenuse and the shorter leg be A. We know that point A must have the largest acute angle in the triangle by construction.
Using any trig function (preferably a easy-calculation one), such as sinA, we can use the inverse function of it to find the angle.
sinA = opposite/hypotenuse = 9/3sqrt(15) = 3sqrt(15)/15 = sqrt(15)/5
Then angle A = arcsin(sqrt(15)/5) = 0.886 radians = 50.8 degrees.
