trigonometry: Cos B= 36^2+25^2-23^2/2x36x23

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trigonometry: Cos B= 36^2+25^2-23^2/2x36x23

Guest Jan 26, 2015

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Best Answer

+130540

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Cos B= (36^2+25^2-23^2)/(2x36x23)

This is solving a Law of Cosines problem for an angle

So, using the cosine inverse, we have

cos^-1 (36^2+25^2-23^2)/(2x36x23) = about 32.8°

CPhill Jan 26, 2015

1⁺⁰ Answers

+130540

+5

Best Answer

Cos B= (36^2+25^2-23^2)/(2x36x23)

This is solving a Law of Cosines problem for an angle

So, using the cosine inverse, we have

cos^-1 (36^2+25^2-23^2)/(2x36x23) = about 32.8°

CPhill Jan 26, 2015

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