\(\frac{1+sin(x)}{cos(x)}+\frac{cos(x)}{1+sin(x)}=\frac{2}{cos(x)}\)
Well here is my steps:
\(\frac{(1+sin^2(x))+cos^2(x)}{cos(x)(1+sin(x))}\)
\(\frac{2+2sin(x)}{cos(x)(1+sin(x))}\)
What to do from here?
+23246 On the left-hand side, when you multiplied [ 1 + sin(x) ] times another [ 1 + sin(x) ],
you should get: [ 1 + sin(x) ]2 = 1 + 2sin(x) + sin2(x)
Then continue ...
Hello geno,
I continued this step but didn't write it
I.e. here it is:
\(\frac{1+sin^2(x)+2sin(x)+cos^2(x)}{cos(x)(1+sin(x))}\)
\(sin^2(x)+cos^2(x)=1\)
Thus we have:
\(1+1+2sin(2)/cos(x)(1+sin(x))\)
Which is
\(\frac{2+2sin(x)}{cos(x)(1+sin(x))}\) So the required is this should be simplified to be 2/cos(x)
