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My answer is D. Is that right? If not, what is the right answer and how did you get it?


 


Use a rotation matrix to rotate figure DEFGH clockwise 90º. If the figure has coordinates D (1, 3), E (3, 2), F (1, -1), G (-3, -2), and H (-2, 2), which statement is true about figure D'E'F'G'H'?









 


A) E' = (2, -3)




 




 


B) G' = (2, 2)




 




 


C) F' = (1, 1)




 




 


D) H' = (-2, 3)




 




 Oct 17, 2014

Best Answer 

 #1
avatar+130511 
+5

I don't think your answer is correct....rotating (-2,2) 90 degrees clockwise puts us in the 1st quadrant. And since H is already in the 2nd quadrant at (-2, 2), it can't remain in the 2nd quadrant at (-2,3).  The likely candidate for the correct answer is A. Follow the logic...If E is in the 1st quadrant, its x and y coordinates are positive. Then, rotating it 90 degrees clockwise would put it in the 4th quadrant....Hence, the x coordinate would be positive and the y coordinate would be negative....  the rotational matrix for this is given by

|   cos90    sin90  |   

| -sin90    cos 90  |

 

So we have

|   cos90    sin90  |    x  l 3 l

| -sin90    cos 90  |       l 2 l        .....  and this gives.......

 

(3 cos 90 + 2 sin 90) = ( 0 + 2) = 2 ......for the resulting x  coordinate

And ( -3sin 90 + 2cos 90)= (-3 + 0 )  = -3 .......for the resulting y coordinate

Yup...just as I suspected !!!.....the resulting point is (2. -3) and "A" is the correct choice.....

 

 Oct 18, 2014
 #1
avatar+130511 
+5
Best Answer

I don't think your answer is correct....rotating (-2,2) 90 degrees clockwise puts us in the 1st quadrant. And since H is already in the 2nd quadrant at (-2, 2), it can't remain in the 2nd quadrant at (-2,3).  The likely candidate for the correct answer is A. Follow the logic...If E is in the 1st quadrant, its x and y coordinates are positive. Then, rotating it 90 degrees clockwise would put it in the 4th quadrant....Hence, the x coordinate would be positive and the y coordinate would be negative....  the rotational matrix for this is given by

|   cos90    sin90  |   

| -sin90    cos 90  |

 

So we have

|   cos90    sin90  |    x  l 3 l

| -sin90    cos 90  |       l 2 l        .....  and this gives.......

 

(3 cos 90 + 2 sin 90) = ( 0 + 2) = 2 ......for the resulting x  coordinate

And ( -3sin 90 + 2cos 90)= (-3 + 0 )  = -3 .......for the resulting y coordinate

Yup...just as I suspected !!!.....the resulting point is (2. -3) and "A" is the correct choice.....

 

CPhill Oct 18, 2014

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