Please help with this question. Thank you!
The point is (2, -2)
r = √ [ (2)^2 + (-2)^2 ] = √8 = 2√2
θ = arctan ( -2/2) = arctan (-1) = -45° = -pi/4 = (2pi - pi/4) = (8pi/4 - pi/4) = 7pi/4
So
2√2 ( cos 7pi/4 + i sin 7pi/4 )
