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Please help with this question. Thank you!

 Apr 19, 2019
 #1
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The point is    (2, -2)

 

r  = √ [ (2)^2 + (-2)^2 ]  = √8  = 2√2

 

θ  =  arctan ( -2/2)  = arctan (-1)  =   -45°   = -pi/4   =  (2pi - pi/4)  =  (8pi/4 - pi/4)  = 7pi/4

 

So

 

2√2 ( cos  7pi/4  +  i sin 7pi/4 )

 

 

cool cool cool

 Apr 19, 2019

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