Solve for θ in the equation cos θ = -0.181 when 180º < θ < 360º. Round your answer to the nearest tenth of a degree.
+130511 Solve for θ in the equation cos θ = -0.181 when 180º < θ < 360º. Round your answer to the nearest tenth of a degree.
We can use the cosine inverse to find this...
cos-1(-.181) = 100.42801238727° ....or about 100.4° However, the cosine is also negative in the 3rd quadrant...so we're looking for a (180- 100.42801238727)° = 79.57198761273° angle in that quadrant =
(180 + 79.57198761273)° = 259.57198761273°..... or about 259.6°
So the answer you're looking for is the second one, i.e., about 259.6°
+130511 Solve for θ in the equation cos θ = -0.181 when 180º < θ < 360º. Round your answer to the nearest tenth of a degree.
We can use the cosine inverse to find this...
cos-1(-.181) = 100.42801238727° ....or about 100.4° However, the cosine is also negative in the 3rd quadrant...so we're looking for a (180- 100.42801238727)° = 79.57198761273° angle in that quadrant =
(180 + 79.57198761273)° = 259.57198761273°..... or about 259.6°
So the answer you're looking for is the second one, i.e., about 259.6°
