To secure a 618-meter radio tower against high winds, guy wires are attached to a ring on the tower. The ring is 9 meters from the top. The wires form a 76o angle with the ground. To the nearest hundredth meter find the length of the guy wire
You use the fact that the sine of an angle is opposite over hypotenuse here.
opposite = 618 - 9 = 609m
so sin(76°) = 609/h
h = 609/sin(76°)
$${\mathtt{h}} = {\frac{{\mathtt{609}}}{\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\mathtt{76}}^\circ\right)}}} \Rightarrow {\mathtt{h}} = {\mathtt{627.643\: \!700\: \!274\: \!085\: \!654\: \!1}}$$
so h = 627.64m to the nearest hundredth of a meter.
You use the fact that the sine of an angle is opposite over hypotenuse here.
opposite = 618 - 9 = 609m
so sin(76°) = 609/h
h = 609/sin(76°)
$${\mathtt{h}} = {\frac{{\mathtt{609}}}{\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\mathtt{76}}^\circ\right)}}} \Rightarrow {\mathtt{h}} = {\mathtt{627.643\: \!700\: \!274\: \!085\: \!654\: \!1}}$$
so h = 627.64m to the nearest hundredth of a meter.