find the height of a balloon directly above a town A if the angle of depression of town B, 6.23 miles from A is 15 degrees 20 minutes
We have
20' = [20/60]° = [1/3]°
tan ( 15 + 1/3) = H / 6.23 where H is the height we are looking for.....solve for H
H = 6.23 tan (15 + 1/3) = about 1.71 mi
+185 
