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Hello! 

Could someone help me work through this problem? I'm not really sure how to get it in the correct form. Thank you.

 Dec 5, 2018
 #1
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what you do with these is multiply top and bottom by the complex conjugate of the denominator

 

\(\dfrac{7+9i}{1+3i}=\dfrac{7+9i}{1+3i} \dfrac{1-3i}{1-3i} = \\ \dfrac{(7+27)+(9-21)i}{10} = \dfrac{34-12i}{10} = \\ \dfrac{17}{5} -\dfrac 6 5 i\)

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 Dec 5, 2018
 #2
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+1

Thank you so much!!! It helped a ton!

Guest Dec 5, 2018

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