Hello!

Could someone help me work through this problem? I'm not really sure how to get it in the correct form. Thank you.

what you do with these is multiply top and bottom by the complex conjugate of the denominator

\(\dfrac{7+9i}{1+3i}=\dfrac{7+9i}{1+3i} \dfrac{1-3i}{1-3i} = \\ \dfrac{(7+27)+(9-21)i}{10} = \dfrac{34-12i}{10} = \\ \dfrac{17}{5} -\dfrac 6 5 i\)

Thank you so much!!! It helped a ton!