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Trigonometry

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245
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Hello!

Could someone help me work through this problem? I'm not really sure how to get it in the correct form. Thank you.

Dec 5, 2018

#1
+6185
+1

what you do with these is multiply top and bottom by the complex conjugate of the denominator

\(\dfrac{7+9i}{1+3i}=\dfrac{7+9i}{1+3i} \dfrac{1-3i}{1-3i} = \\ \dfrac{(7+27)+(9-21)i}{10} = \dfrac{34-12i}{10} = \\ \dfrac{17}{5} -\dfrac 6 5 i\)

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Dec 5, 2018
#2
+1

Thank you so much!!! It helped a ton!

Guest Dec 5, 2018