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(cotalpha cotbeta -1)/(cotalpha +cotbeta )

 Dec 6, 2018
 #1
avatar+228 
+2

Do you want it simplified? It already is. What are you looking for in this expression?

 Dec 6, 2018
 #2
avatar+118703 
+1

(cotαcotβ1)(cotα+cotβ)=cosαcosβsinαsinβsinαsinβ÷(cosαsinα+cosβsinβ)=cosαcosβsinαsinβsinαsinβ÷2cosαsinβsinαsinβ=cosαcosβsinαsinβ2cosαsinβ=cosαcosβsinαsinβ2cosαsinβ=cos(α+β)sin(α+β)=cot(α+β)

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 Dec 7, 2018

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