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A man wishes to fence a lot bounded by street running east and west, another street running north and south, and a third street that bears N32°E. The frontage on the east-west street is 50 m. How many meters of fencing material is needed?

 May 14, 2020
 #1
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The three streets  form a right triangle

 

The east-west   and  north-south streets  are legs  and  the  street  that bears  N 32° E  is  the hypotenuse

 

We  can find the frontage  along the hypotenuse, H,  as follows

 

H/sin 90  =  50/ sin 32

 

H = 50/sin 32  ≈ 94.35 m

 

The lfrontage along the north-south street is

 

sqrt ( 94.35^2 - 50^2 )  ≈ 80 m

 

 

The total fencing needed  =  50 + 80 + 94.35   ≈  224.35 m

 

 

cool cool cool

 May 14, 2020
edited by CPhill  May 14, 2020

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