A man wishes to fence a lot bounded by street running east and west, another street running north and south, and a third street that bears N32°E. The frontage on the east-west street is 50 m. How many meters of fencing material is needed?

Guest May 14, 2020

#1**+1 **

The three streets form a right triangle

The east-west and north-south streets are legs and the street that bears N 32° E is the hypotenuse

We can find the frontage along the hypotenuse, H, as follows

H/sin 90 = 50/ sin 32

H = 50/sin 32 ≈ 94.35 m

The lfrontage along the north-south street is

sqrt ( 94.35^2 - 50^2 ) ≈ 80 m

The total fencing needed = 50 + 80 + 94.35 ≈ 224.35 m

CPhill May 14, 2020