An airplane is headed for the airport, 15 miles away. If the airplane is at an altitude of 5000feet, what is the angle of depression, to the nearest tenth of a degree, from the airplane tothe airport? (1 mile = 5280 feet)
Angle of inclination = Angle of depression
arctan ( 5000 / ( 15 *5280) ) = angle of depression ≈ 3.6°
