Consider a triangle ABC like the one below. Suppose that c=41 , b=28 , and C=114° . (The figure is not drawn to scale.) Solve the triangle. Carry your intermediate computations to at least four decimal places, and round your answers to the nearest tenth.
Can't see any figure. You should always describe the sides as: Opposite side. Adjacent side. Hypotenuse. It makes it a lot easier for the people here to help you, especially when we can't see any figures or pictures.
+118724 I can cope without the pic BUT what does "Solve the triangle. " mean ?????
+130518 sinC / c = sin B / b so we have
sin(114) / 41 = sinB/ 28
sinB = [28* sin (114))/ 41]
sin-1 [28* sin (114))/ 41] = B = about 38.6°
And angle A = about [180 - 114 - 38.6]° = about 27.4°
And side a =
a/sin(27.4) = 41 / sin(114)
a = 41*sin(27.4) / sin(114) = about 20.7 units
