In right triangle ABC, we have AB = 10, BC = 24, and ABC = 60 degrees. If M is AC on such that is an angle bisector of ABC, then what is cos ABM?
Interior angles are 30-60-90
If a short leg AB = 10 then the hypotenuse BC = 20 NOT 24!!!
correct your question
btw, cos of ABM is cos(30º)