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Find algebraically the zeros for p(x)= x^3+x^2-4x-4

 Feb 24, 2017
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x^3+x^2-4x-4  = 0    factor

 

x^2(x + 1) - 4 (x + 1)  = 0

 

(x + 1) (x^2- 4)  = 0

 

(x + 1) (x + 2) ( x - 2)  = 0

 

Set each factor to 0 and x = -1, x = -2  or x = 2

 

 

cool cool cool

 Feb 24, 2017

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