+185 one of the equal sides of an isosceles triangle is 6.73 inches and one of the base angles is 27 degrees 10'. find the base and altitude
+130516 27 ° 10' = [27 + 1/6]°
One of the equal sides will form the hypotenuse of a right triangle......and the altitude will form a leg opposite the given angle.....so we can use the sine function to find the height, H
sin [ 27 + 1/6] = H / 6.73 rearrange to solve for H
H = sin [27 + 1/6] * 6.73 = about 3.07 in
We can find the length of 1/2 of the base using the Pythagorean Theorem, since this will equal the remaining leg =
1/2 of the base = √[ 6.73^2 - 3.07^2] = about 5.98 in
So....the base = twice this = about 11.96 in
