A driveway has a 15% grade (slope). If the driveway is 12 m long, to the nearest tenth of a meter, how much does it rise?
15%x12?
+118723 $$slope=gradient=15\%=\frac{rise}{run}=\frac{15}{100}=\frac{3}{20}$$
Now the driveway is 12m long and we need to find the rise SO
$$\frac{3}{\sqrt{409}}=\frac{rise}{12}\\\\
\frac{36}{\sqrt{409}}=rise\\\\
rise\approx 1.780085m\\\\
rise\approx 1.8m\qquad \mbox{to the nearest 10th of a metre}$$
I think it is just coincidence that the 2 answers are the same.
Would another mathematician arbitrate please.
+118723 $$slope=gradient=15\%=\frac{rise}{run}=\frac{15}{100}=\frac{3}{20}$$
Now the driveway is 12m long and we need to find the rise SO
$$\frac{3}{\sqrt{409}}=\frac{rise}{12}\\\\
\frac{36}{\sqrt{409}}=rise\\\\
rise\approx 1.780085m\\\\
rise\approx 1.8m\qquad \mbox{to the nearest 10th of a metre}$$
I think it is just coincidence that the 2 answers are the same.
Would another mathematician arbitrate please.
