At a horizontal distance of 34 meters from the base of a tower, the angle of elevation to the top is 72 degrees. Find the height of the tower to the nearest tenth of a meter.
How would I set this up as a drawing
+130511 Something like this:
AB is the horizontal distance from the base (34m) and BC is the height (104.64m) of the tower.
+130511 Note that we know an angle and an adjacent side to that angle. And we want to find the opposite side.....
( the tower's height). The function that relates these is the tangent.
So we have....
tan(72) = opp/34 .......multiply both sides by 34
34tan(72) = opp ≈ 104.64m
