in the interval 0 < x < 360, find the values of x for which sin x = 0.6691

Guest Mar 5, 2017

sin x = 0.6691

x = arcsin(0.6691)


x1 ≈ 41.998º


This is only the angle that makes the sinx  = 0.6691 in the first quadrant.

The other angle that makes sinx = 0.6691 will be in the second quadrant.

The third and fouth quadrants all have negative sin values.

So to find the other angle all you gotta do is subtract  41.998º from 180º


x≈ 180 - 41.998

x2 ≈ 138.002°

hectictar  Mar 5, 2017

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