a telegraph pole is braced by wires from the ground which are attached at a point 18.6 feet up the pole. find the length of a wire that makes an angle of 26 degress 20' with the vertical.
26 degrees 20 minutes is 26.333 degrees
sin 26.333 = 18.6/hyp
hyp = 18.6/sin26.33 =41.92 ft
26° 20' = [26 + 1/3]°
The wire forms the the hypotenuse of a right triangle, with the 18.6 ft being the leg opposite the given angle.......so.....we can use the sine function to find the length of the wire
sin [26 + 1/3] = 18.6 / L where L is the wire length .....rearrange to solve for L
L = 18.6 / sin[26 + 1/3] = about 41.93 ft