+308 I have the answer, just not the steps. Can you give me the steps Electric?
+37146 I just did it in my head....but you can (again) use the Quadratic formula to fin the values of x
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(x = {-1 \pm \sqrt{1^2-4(1)(-2)} \over 2(1)}\) x = -1/2 +- (sqrt9)/2 = -1/2+- 3/2 = -2 or 1
so the roots are -2 or 1 x+2 or x-1 so (x+2)(x-1)=0 results in x=-2 or 1
