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1 + cot^2 (x) = [4 cos^2 (x) / (sin^2 (2x))]

 Nov 20, 2020
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1 + cot^2 (x) = [4 cos^2 (x) / (sin^2 (2x))]

 

Hello Guest!

 

\(1 + cot^2 (x) =\frac{ 4 cos^2 (x)} { sin^2 (2x)}\)

\(1 + cot^2 (x) =\frac{ 4 cos^2 (x)} { 4sin^2(x)cos^2(x)} \)

\(1 + cot^2 (x) =\frac{1}{sin^2(x)}\\ sin^2(x)=\frac{1}{1+cot^2(x)}\)  True!

laugh  !

 Nov 20, 2020
edited by asinus  Nov 20, 2020

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