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Hey I’m back with more trig questions answers are greatly appreciated thanks :)

 

1. Find () given sin()= .8543

 

2. Find the magnitude of the reference angle for ()=(11pi)/5

 

3. Evaluate csc 4.92

 

4. Find sec () given that () lies in Quadrant III and tan()= 6

KaylaRT  Nov 6, 2017
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3+0 Answers

 #1
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1. Find () given sin()= .8543

 

Use the sine inverse  [ arcsin] to find { }

 

arcsin [ .8543 ]  ≈  58.68°  =  {}

 

 

2. Find the magnitude of the reference angle for ()=(11pi)/5

 

Convert radians to degrees   using     180  /pi         ...so we have

 

(11/5) pi  *  [ 180 / pi ]   =

 

[11 / 5 ] pi  *  [ 180 / pi ]  =

 

11 *  180  / 5  =

 

11 * 36  =

 

336°

 

 

3. Evaluate csc 4.92

 

csc 4.92   ≈  -1.021945      [ 4.92 is in radians ]

 

 

 

4. Find sec () given that () lies in Quadrant III and tan()= 6

 

tan  =  y/x      so ..in  Quad III      y = -6   and x  =  - 1

 

sec  =   x / r       and we can find r  as   

sqrt  [ x^2 + y^2] =  sqrt [ (-1)^2 + (- 6)^2] =

sqrt [ 1 + 36 [  =   sqrt [ 37]  = r

 

So  sec  =     x / r  =     -1 / sqrt [37]    [   or    -sqrt [ 37] / 37 .... if you prefer ]

 

 

cool cool cool

CPhill  Nov 6, 2017
edited by CPhill  Nov 6, 2017
 #2
avatar+15 
+2

Omg thanks! You are a lifesaver!

KaylaRT  Nov 6, 2017
 #3
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Is that even your photo? Cause I found it on Google 

Arya_Lynn  Nov 6, 2017

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